For graph given write an inequation taking x as the variable
Question types
Linear Inequations (In one variable) question types
80 questions across 4 question groups — pick any mix to generate a Mathematics paper with step-by-step answer keys.
80
Questions
4
Question groups
5
Question types
01
[1 Mark Question Answer]
6 Q→02[2 Mark Question Answer]
44 Q→03[3 marks sum]
20 Q→04TRUE / FALSE
10 Q→Sample Questions
Linear Inequations (In one variable) questions
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
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For graph given write an inequation taking x as the variable
For graph given write an inequation taking x as the variable
For graph given write an inequation taking x as the variable
Given A = {x: -1 < x ≤ 5, x ∈ R} and B = {x: -4 ≤ x < 3, x ∈ R}
Represent on different number lines:
Represent on different number lines:
A – B
List the elements of the solution set of the inequation
-3 < x – 2 ≤ 9 – 2x; x ∈ N.
Represent the solution of the given inequalities on the real number line
$\frac{2 x+5}{3}>3 x-3$
View full solution →$\frac{2 x+5}{3}>3 x-3$
Represent the solution of the given inequalities on the real number line
$1+x \geq 5 x-11$
View full solution →$1+x \geq 5 x-11$
Represent the solution of the given inequalities on the real number line
$2 - 3x > 7 - 5x$
View full solution →$2 - 3x > 7 - 5x$
Represent the solution of the given inequalities on the real number line
$x+3 \leq 2 x+9$
View full solution →$x+3 \leq 2 x+9$
Given x ∈ {real numbers}, find the range of values of x for which -5 ≤ 2x – 3 < x + 2 and represent it on a number line.
Find the range of values of x which satisfies
$-2 \frac{2}{3} \leq x+\frac{1}{3}<3 \frac{1}{3} ; x \in R$
Graph these values of x on the number line.
View full solution →$-2 \frac{2}{3} \leq x+\frac{1}{3}<3 \frac{1}{3} ; x \in R$
Graph these values of x on the number line.
x ∈ {real numbers} and -1 < 3 – 2x ≤ 7, evaluate x and represent it on a number line.
Solve the following inequation, write the solution set and represent it on the number line.
$-3(x-7) \geq 15-7 x>\frac{x+1}{3}, x \in R$
View full solution →$-3(x-7) \geq 15-7 x>\frac{x+1}{3}, x \in R$
Solve the following in equation and write the solution set:
13x - 5 < 15x + 4 < 7x + 12, x ∈ R
Represent the solution on a real number line.
13x - 5 < 15x + 4 < 7x + 12, x ∈ R
Represent the solution on a real number line.
If a < b, and c > 0, then a – c < b – c
Where a, b, c and d are real numbers and c ≠ 0.
Where a, b, c and d are real numbers and c ≠ 0.
State,Whether the following statements is true or false:
If a – c > b – d, then a + d > b + c
If a – c > b – d, then a + d > b + c
State,Whether the following statements is true or false:
if $a > b$ then $\frac{a}{c}<\frac{b}{c}$
View full solution →if $a > b$ then $\frac{a}{c}<\frac{b}{c}$
IF a < b, then ac < bc
State,Whether the following statements is true or false:
If a > b, then a + c > b + c
If a > b, then a + c > b + c
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