MCQ

MCQ 11 Mark

The sum of two rational numbers is -1 . If one of them is $\frac{-5}{7}$, then the other is

A
$\frac{5}{7}$
B
$\frac{-2}{7}$
C
$\frac{12}{7}$
D
$\frac{-12}{7}$

Answer

The sum of two rational number is -1
One of them $=\frac{-5}{7}$
The other will be $=-1-\left(\frac{-5}{7}\right)=-1+\frac{5}{7}$
$=\frac{-7+5}{7}=\frac{-2}{7}$ (b)

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MCQ 21 Mark

In the standard form of a rational number, the denominator is always

A
$0$
B
a negative integer
C
1
D
a positive integer

Answer

In a standard form of a rational number, the denominator is always a positive integer. (d)

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MCQ 31 Mark

$\left(-2 \frac{1}{3}\right) \div 2 \frac{11}{12}$ is equal to

A
$-\frac{4}{5}$
B
$\frac{4}{5}$
C
$\frac{4}{11}$
D
$-\frac{4}{11}$

Answer

$\begin{array}{c}
\left(-2 \frac{1}{3}\right) \div 2 \frac{11}{12}=\frac{-7}{3} \div \frac{35}{12} \\
=\frac{-7}{3} \times \frac{12}{35}=\frac{-4}{5}\ \text{(a)}
\end{array}
$

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MCQ 41 Mark

$\left(-5 \frac{1}{3}\right) \times\left(-1 \frac{7}{8}\right)$ is equal to

A
10
B
$-10$
C
$5 \frac{7}{24}$
D
$-5 \frac{7}{24}$

Answer

$\left(-5 \frac{1}{3}\right) \times\left(-1 \frac{7}{8}\right)=\frac{16}{3} \times \frac{15}{8}=10$ (a)

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MCQ 51 Mark

$\frac{-3}{5}-\left(\frac{-2}{15}\right)$ is equal to

A
$\frac{-11}{5}$
B
$\frac{-1}{15}$
C
$\frac{-7}{15}$
D
$\frac{7}{15}$

Answer

$\begin{array}{c}
\frac{-3}{5}-\left(\frac{-2}{15}\right)=\frac{-3}{5}+\frac{2}{15} \\
=\frac{-9+2}{15}=\frac{-7}{15}\ \text{(c)}
\end{array}$

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MCQ 61 Mark

The sum of rational number $\frac{-1}{3}$ and its reciprocal is

A
$0$
B
1
C
$\frac{-10}{3}$
D
(\frac{-3}{10}$

Answer

Reciprocal of $\frac{-1}{3}$ is $\frac{-3}{1}$
Sum of rational number and its reciprocal
$=\frac{-1}{3}+\left(\frac{-3}{1}\right)=\frac{-1-9}{3}=\frac{-10}{3}$ $\text{(c)}$

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MCQ 71 Mark

The product of rational number $\frac{-2}{3}$ and its additive inverse is