[2 Mark Question Answer]

Question 12 Marks

Define the term density of a substance.

Answer

The density of the substance can be define as the ratio of mass of substance with respect to the volume of the substance.
$\rho=\frac{m}{V}$

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Question 22 Marks

The mass of an iron ball is 312 g . The density of iron is $7.8 g cm ^{-3}$. Find the volume of the ball.

Answer

Given, Mass $M=312 \mathrm{~g}$
Density $d=7.8 \mathrm{~g} \mathrm{~cm}^{-3}$
Since, $d=\frac{M}{V} \Rightarrow V=\frac{M}{d}$
Hence, vollume of an iron ball $V=\frac{312}{78}=40 \mathrm{~cm}^3$

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Question 32 Marks

A rectangular field is of length $60 \ m$ and breadth $35\ m.$ Find the area of the field.

Answer

Length of a rectangular field $=60 m$
Breadth of rectangular field $=35 m$
$\therefore \text { Area }=60 m \times 35 m$
$=2100 m^2$

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Question 42 Marks

Find the volume of a liquid present in a dish of dimensions $10 cm x 10 cm x 5 cm.$

Answer

Volume of water = Length × breadth × height
$= 10 cm \times 10 cm \times 5 cm$
$= 500 cm^3 or 500 ml.$

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Question 52 Marks

The density of copper is $8.9 g cm^{-3}$. What will be its density in $kg m^{-3} ?$

Answer

Density of copper
$\begin{aligned} \mathrm{d} & =8.9 \mathrm{~g} \mathrm{~cm}^{-3}
\\ & =8.9 \times 1000 \mathrm{~kg} \mathrm{~m}^{-3}
\\ & {\left[\therefore 1 \mathrm{~g} \mathrm{~cm}^{-3}=1000 \mathrm{~kg} \mathrm{~m}^{-3}\right] }
\\ & =8900 \mathrm{~kg} \mathrm{~m}^{-3}\end{aligned}$

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PHYSICS [2 Mark Question Answer]

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