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19 questions · timed · auto-graded

MCQ 11 Mark
If $\left(x-\frac{1}{x}\right)=3$, then $\left(x^2+\frac{1}{x^2}\right)$ is equal to
  • A
    7
  • B
    9
  • 11
  • D
    none of these
Answer
Correct option: C.
11
C
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MCQ 21 Mark
What must be added to $\left(4 x^2+20 x+16\right)$ so that it becomes a perfect square?
  • 9
  • B
    12
  • C
    15
  • D
    20
Answer
Correct option: A.
9
A
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MCQ 71 Mark
If $\left(x^2+\frac{1}{x^2}\right)=102$, then the value of $\left(x-\frac{1}{x}\right)$ is
  • A
    8
  • 10
  • C
    12
  • D
    13
Answer
Correct option: B.
10
B
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MCQ 81 Mark
If $\left(x+\frac{1}{x}\right)=4$, then $\left(x^4+\frac{1}{x^4}\right)$ is equal to
  • A
    190
  • B
    192
  • 194
  • D
    196
Answer
Correct option: C.
194
C
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MCQ 91 Mark
If $\left(x+\frac{1}{x}\right)=\frac{17}{4}$, then the value of $\left(x-\frac{1}{x}\right)$ is
  • A
    4
  • B
    $\frac{1}{4}$
  • C
    $\frac{13}{4}$
  • $\frac{15}{4}$
Answer
Correct option: D.
$\frac{15}{4}$
D
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MCQ 101 Mark
$\left(x+\frac{1}{x}\right)^2-\left(x-\frac{1}{x}\right)^2=?$
  • A
    $0$
  • 4
  • C
    2
  • D
    $2\left(x^2+\frac{1}{x^2}\right)$
Answer
Correct option: B.
4
B
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MCQ 111 Mark
Which of the following is not equal to $\left(a^2+b^2\right)$ ?
  • A
    $(a+b)^2-2 a b$
  • B
    $(a-b)^2+2 a b$
  • $\frac{1}{2}\left\{(a+b)^2-(a-b)^2\right\}$
  • D
    $\frac{1}{2}\left\{(a+b)^2+(a-b)^2\right\}$
Answer
Correct option: C.
$\frac{1}{2}\left\{(a+b)^2-(a-b)^2\right\}$
C
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MCQ 121 Mark
If $\left(x+\frac{1}{x}\right)=3$, then $\left(x^2+\frac{1}{x^2}\right)$ is equal to
  • A
    $\frac{10}{3}$
  • B
    $\frac{82}{9}$
  • 7
  • D
    11
Answer
Correct option: C.
7
C
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MCQ 131 Mark
Which of the following will be equal to $98 \times 102$ ?
  • A
    $102^2-98^2$
  • $100^2-2^2$
  • C
    $101^2-2^2$
  • D
    none of these
Answer
Correct option: B.
$100^2-2^2$
B
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MCQ 141 Mark
$\left(x^4-1\right) \div(x-1)$ is:
  • A
    $x^3-1$
  • B
    $x^3$
  • C
    $(x-1)\left(x^2-1\right)$
  • $(x+1)\left(x^2+1\right)$
Answer
Correct option: D.
$(x+1)\left(x^2+1\right)$
D
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MCQ 151 Mark
If $x^2+\frac{1}{x^2}=627$, then the value of $\left(x-\frac{1}{x}\right)$ is:
  • 25
  • B
    26
  • C
    28
  • D
    $\sqrt{26}$
Answer
Correct option: A.
25
A
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MCQ - MATHS STD 8 Questions - Vidyadip