Question 13 Marks
Construct angle $ABC = 90^\circ$ . Draw $BP$, the bisector of angle $ABC$. State, the measure of angle $PBC$.
Answer
View full question & answer→Draw$ \angle ABC = 90^\circ$
Draw bisector of $\angle ABC$
Then $\angle \mathrm{PBC}=\frac{1}{2}\left(90^{\circ}\right)=45^{\circ}$
Draw bisector of $\angle ABC$
Then $\angle \mathrm{PBC}=\frac{1}{2}\left(90^{\circ}\right)=45^{\circ}$