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6 questions · timed · auto-graded

MCQ 11 Mark
Probability of getting a non-red ball from a bag containing $4$ red, $5$ blue and $3$ black balls is
  • A
    $\frac{1}{3}$
  • $\frac{2}{3}$
  • C
    $\frac{1}{4}$
  • D
    $\frac{5}{12}$
Answer
Correct option: B.
$\frac{2}{3}$
In a bag, there are $4$ red balls, $5$ blue and $3$ black balls.
$\therefore$ Total outcomes $=4+5+3=12$
Probability of a non$-$red ball $( 5$ blue $+3$ black$) =8$
$=\frac{8}{12}=\frac{2}{3}$
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MCQ 21 Mark
Probability of getting a red ball from a bag containing $20 $ red balls
  • A
    $0$
  • $1$
  • C
    $\frac{1}{20}$
  • D
    $\frac{1}{2}$
Answer
Correct option: B.
$1$
Total red balls $=20$
Probability a red ball $=\frac{20}{20}=1$
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MCQ 31 Mark
Probability of getting more than $2$ heads when a pair of coins is tossed.
  • A
    $1$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{3}$
  • $0$
Answer
Correct option: D.
$0$
A pair of coins tossed, then
Total number of outcomes $= 2 \times 2 = 4$
Getting more than two heads $–$ None
$\therefore$ Probability $= 0$
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MCQ 41 Mark
Probability of selecting a consonant from the letters of the word $\text{‘FATHER'}$
  • A
    $\frac{1}{3}$
  • B
    $\frac{3}{4}$
  • C
    $\frac{5}{6}$
  • $\frac{2}{3}$
Answer
Correct option: D.
$\frac{2}{3}$
From the letter $\text{‘FATHER}’$
Total outcomes $=6$
$\therefore$ Consonant $=\frac{4}{6}=\frac{2}{3}$
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MCQ 51 Mark
Probability of getting exactly $2$ heads when three coins are tossed together
  • A
    $\frac{1}{8}$
  • B
    $\frac{1}{4}$
  • $\frac{3}{8}$
  • D
    $\frac{5}{8}$
Answer
Correct option: C.
$\frac{3}{8}$
Three coins are tossed, then total number of outcomes $=2^3=2 \times 2 \times 2=8$
Getting two heads $(2,2 \ldots),(2 \ldots, 2),(\ldots 2,2)=3$
Probability $=\frac{3}{8}$ 
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MCQ 61 Mark
Probability of getting the sum as $4$ when a pair of dice is rolled
  • A
    $\frac{3}{4}$
  • $\frac{1}{12}$
  • C
    $\frac{1}{9}$
  • D
    $\frac{1}{6}$
Answer
Correct option: B.
$\frac{1}{12}$
A pair of dice is rolled, then total number of outcomes $=6 \times 6=36$
Getting sum as $4(1,3),(2,2),(3,1)=3$
Probability $P ( E )=\frac{3}{36}=\frac{1}{12}$ 
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MCQ - MATHS STD 8 Questions - Vidyadip