Question 15 Marks
Show by division method that $\left(2 a^2-a+3\right)$ is a factor of $\left(6 a^5-a^4+4 a^3-5 a^2-a-15\right)$.
Answer
View full question & answer→[Hint : Divide $\left(6 a^5-a^4+4 a^3-5 a^2-a-15\right)$ by $\left(2 a^2-a+3\right)$ and show that the remainder is 0.]