Question 15 Marks

Two coins are tossed together. What is the probability of getting : $(i)$ at least one head $(ii)$ both heads or both tails.

Answer

$\because$ A coin has two faces Head and Tail or $H_1 T$
$\therefore$ Two coins are tossed
$\therefore$ Number of coins $=2 \times 2=4$
which are $HH , HT , TH , TT$
$(i)$ At least one head, then
Number of outcomes $=3$
$\therefore P(E)=\frac{\text { Number of favourable outcome }}{\text { Number of all possible outcome }}$
$ =\frac{3}{4}$
$(ii)$ When both head or both tails, then
Number of outcomes $=2$
$\therefore P(E)=\frac{\text { Number of favourable outcome }}{\text { Number of all possible outcome }}$
$\frac{2}{4}=\frac{1}{2}$

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