Question 13 Marks
Can a polyhedron have $8$ faces, $26$ edges, and $16$ vertices?
Answer
View full question & answer→Number of faces $= 8$
Number of vertices $= 16$
Number of edges $= 26$
Using Euler’s formula
$F + V – E$
$\Rightarrow 8 + 16 – 26 \neq -2$
$\Rightarrow -2 \neq 2$
No, a polyhedron cannot have $8$ faces, $26$ edges, and $16$ vertices.
Number of vertices $= 16$
Number of edges $= 26$
Using Euler’s formula
$F + V – E$
$\Rightarrow 8 + 16 – 26 \neq -2$
$\Rightarrow -2 \neq 2$
No, a polyhedron cannot have $8$ faces, $26$ edges, and $16$ vertices.


