Question 11 Mark
A force of $45\ N$ displace a chair by $0.5\ m$. What is the amount of work done ?
Answer
View full question & answer→Force applied on the chair, $F = 45\ N$
Displacement of the chair, $5 = 0.5\ m$
Amount of work done, $W = F \times s$
$= (45\ N) \times (0.5\ m) = 22.5\ J$
Displacement of the chair, $5 = 0.5\ m$
Amount of work done, $W = F \times s$
$= (45\ N) \times (0.5\ m) = 22.5\ J$