Question 11 Mark
Find approximate value of $\frac{1}{4.08}$ upto four places of decimals.
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$(2-3 x)^{1 / 3}$
$(1+3 x)^{-1 / 2}$
$(1+2 x)^{-4}$
$\left(1+x^2\right)^{-1}$
$\left(1-x^2\right)^{-3}$
$(1+x)^{-4}$