Question types

Hyperbola question types

64 questions across 4 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

64
Questions
4
Question groups
5
Question types
Sample Questions

Hyperbola questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1MCQ1 Mark
Equation of the hyperbola whose vertices are $(\pm3,0)$ and foci at $(\pm5,0),$ is
  • $16x^2 - 9y^2 = 144$
  • B
    $9x^2 - 16y^2 = 144$
  • C
    $25x^2 - 9y^2 = 225$
  • D
    $9x^2 - 25y^2 = 81$

Answer: A.

View full solution
Q 2MCQ1 Mark
If $e_1$ and $e_2$ are respectively the eccentricities of the ellipse $\frac{\text{x}^2}{18}+\frac{\text{y}^2}{4}=1$ and the hyperbola $\frac{\text{x}^2}{9}-\frac{\text{y}^2}{4}=1,$ then the relation between $e_1$ and $e_2$ is
  • A
    $3\text{e}_1^2 + \text{e}_2^2 = 2$
  • B
    $\text{e}_1^2 + 2\text{e}_2^2 = 3$
  • $2\text{e}_1^2 +\text{e}_2^2 = 3$
  • D
    $\text{e}_1^2 + 3\text{e}_2^2 = 2$

Answer: C.

View full solution
Q 3MCQ1 Mark
The eccentricity of the hyperbola $x^2 - 4y^2 = 1$
  • A
    $\frac{\sqrt3}{2}$
  • ${\frac{\sqrt5}{2}}$
  • C
    ${\frac{2}{\sqrt3}}$
  • D
    $\frac{2}{\sqrt5}$

Answer: B.

View full solution
Q 4MCQ1 Mark
The distance between the directrices of the hyperbola $\text{x}=8\sec\theta,\text{y}=8,$ is
  • $8\sqrt2$
  • B
    $16\sqrt2$
  • C
    $4\sqrt2$
  • D
    $6\sqrt2$

Answer: A.

View full solution
Q 5MCQ1 Mark
The equation of the conic with focus at $(1, -1)$ directrix along $x - y + 1 = 0$ and eccentricity $\sqrt2$ is
  • A
    $xy = 1$
  • B
    $2xy + 4x - 4y - 1 = 0$
  • C
    $x^2 - y^2 = 1$
  • $2xy - 4x + 4y + 1 = 0$

Answer: D.

View full solution

Generate a Hyperbola paper free

Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.

Download App