Question 13 Marks
If $A^{-1}=\frac{1}{3}\left[\begin{array}{ccc}1 & 4 & -2 \\ -2 & -5 & 4 \\ 1 & -2 & 1\end{array}\right]$ and $|A|=3$, then (adj. $\left.A\right)=\ldots$.
Answer
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3 questions · timed · auto-graded