3 Mark Question

Question 13 Marks

What number added to 3.56 gives 23.018?

Answer

Let the required number be x.
According to the question,
3.56 + x = 23.018
⇒ x = 23.018 - 3.5

⇒ x = 19.458
Hence, 19.458 when added to 3.56 gives 23.018.

Question 23 Marks

Sunita travels 15km 268m by bus, 7km 7m by car and 500m by foot in order to reach her school. How far is her school from her residence?

Answer

Distance travelled by bus = 15km 268m = 15.268km
Distance travelled by car = 7km 7m = 7.007km
Travel on foot = 500m = 0.500km
Total distance travelled by sunita = (15.268 + 7.07 + 0.500)km
= 22.775km
Therefore, the total distance covered by sunita is 22.775km

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Question 33 Marks

Ruby bought a watermelon weighing 5kg 200g. Out of this she gave 2kg 750g to her neighbour. What is the weight of the watermelon left with Ruby?

Answer

Weight of the watermelon when bought = 5kg 200g = 5.200kg
Weight of the watermelon given to the neighbor = 2kg 750g = 2.750kg.
Therefore, weight of the watermelon left with ruby = Weight of the watermelon when bought - Weight of the watermelon when given to the neighbor,
= (5.200 - 2.750)kg
= 2.450kg
So, the weight of the water melon left with ruby = 2.450kg.

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Question 43 Marks

Tina had 20m 5cm long cloth. She cuts 4m 50cm length of cloth form this for making a curtain. How much cloth is left with her?

Answer

Length of cloth originally = 20m 5cm = 2.05m
Length of cloth cut for curtain = 4m 50cm = 4.50m
Therefore, length of cloth left with tina = length of cloth originally - length of cloth cut for curtain,
= 20.05 - 4.50m
= 15.55m
Length of the cloth left with tina = 15.55m.

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Question 53 Marks

Tanuj walked 8.62km on Monday, 7.05km on Tuesday, and some distance on Wednesday. If he walked 21.01km in three days, how much distance did he walk on Wednesday?

Answer

Distance travelled on Monday = 8.62km
Distance travelled on Tuesday = 7.05km
Suppose the distance travelled on Wednesday = x km
Total distance covered,
= 21.01 = 8.62 + 7.05 + x
= x = 21.01 - 15.67
= x = 5.34
Therefore, Tanuj walked 5.34km on Wednesday.

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Question 63 Marks

Shikha bought 2m 5cm cloth for her salwar and 3m 35cm cloth for her shirt. Find the total length of cloth bought by her.

Answer

Cloth required for salwar = 2m 05cm = 2.05m
Cloth required for shirt = 3m 35cm = 3.35m
Total cloth required is:
$\underline{\ \ \ \ \ \ \ _1\\\ \ \ \ 2.05\text{m}\\+3.35\text{m}}\\\underline{\ 5\ .\ 40\text{m}}$
Hence, the total length of cloth bought by Shikha is 5.4m.

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Question 73 Marks

What number subtracted from 18.5 gives 6.2376?

Answer

Let the required number be x. According to the question, 18.5 - x = 6.2376 ⇒ x = 18.5 - 6.2376

⇒ x = 12.2624 Hence, 12.2624 subtracted from 18.5 gives 6.2376.

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Question 83 Marks

By how much should 27.354 be increased to get 52?

Answer

Let the required value be x.
According to the question,
27.354 + x = 52
⇒ x = 52 - 27.354

⇒ x = 24.646
Hence, 24.646 should 27.354 be increased to get 52.

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Question 93 Marks

Gopal travelled 125.5km by bus, 14.25km by pony and the rest of distance of Kedarnath on foot. If he covered a total distance of 150km, how much did he travel on foot?

Answer

Distance travelled by bus = 125.5km
Distance travelled by pony = 14.25km
Suppose the distance travelled on foot = x
Total distance = 150km = distance travelled by bus + distance travelled on pony + distance travelled travelled on foot
= 150 = 125.5 + 14.25 + x
= 150 = 139.75 + x
= x = 10.25km
Therefore, distance travelled on foot= 10.25km.

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Question 103 Marks

Suman purchased 5kg 75g of fruits and 3kg 465g of vegetables, and put them in a bag. If this bag with these contents weighs 9kg, find the weight of the empty bag.

Answer

Weight of fruits = 5kg 75g = 5.075kg.
Weight of vegetables = 3kg 465g = 3.465kg.
Total weight of fruits and vegetables is:
$\underline{\ \ \ \ \ \ \ _1\ _1\\\ \ \ \ 5.075\text{kg}\\+3.465\text{kg}}\\\underline{\ \ \ \ 8.540\text{kg}}$
Now, the bag with these contents weighs 9kg.
Therefore, the weight of empty bag is:

Hence, the weight of the empty bag is 460g.

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Question 113 Marks

Vineeta bought a book for Rs. 18.80, a pen for Rs. 8.50 and some papers for Rs. 5.05. She gave fifty rupee to the shopkeeper. How much balance did she get back?

Answer

Price of the book = Rs. 18.90
Price of the pen = Rs. 8.50
Price of the paper = Rs. 5.05
Total price of three items = Rs. (18.90 + 8.50 + 5.05)
= Rs. 32.45
Total amount given to the shopkeeper = Rs. 50
Balance received = Rs. (50 - 32.45)
= Rs. 17.55

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Question 123 Marks

Evaluate the following:
36.36 - 28.4237 - 9.78 + 7.7

Answer

$36.36 - 28.4237 - 9.78 + 7.7$
$= 36.36 + 7.7 - (28.4237 + 9.78)$
$\underline{\ \ _1\ _1\\\ \ 36.36\\+7.70}\\\underline{\ \ 44.06}$
$\underline{\ \ \ _1\ _1\ _1\\\ \ \ 28.4237\\+\ 9.7800}\\\underline{\ \ \ 38.2037}$
$=44.06-38.2037$

$= 5.8563$

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Question 133 Marks

Convert $2\frac{9}{40}$ into a decimal fraction.

Answer

$2\frac{9}{40}=2+\frac{9}{40}$
$=2+\frac{9\times25}{40\times25}$
$=2+\frac{225}{1000}$
$=2+0.225$
$=2.225$
Hence, the value of $2\frac{9}{40}$ into a decimal fraction is 2.225.

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