Maths MCQ

$=3 \times 0.3 \times 0.03 \times 0.003 \times 30$
$=3\times\frac{3}{10}\times\frac{3}{100}\times\frac{3}{1000}\times3\times10$
$=\frac{3\times3\times3\times3\times3}{100\times1000}$
$=\frac{243}{100000}$
$=0.00243 ($Decimal point is shifted to left by $5$ places$)$

We know that,
$1\text{g}=\frac{1}{1000}\ kg$
Now,
$5\text{kg }5\text{g}=5\ kg+5\text{g}$
$=5\ kg+\frac{5}{1000}\ kg$
$=5\ kg+0.005\ kg$
$=5.005\ kg$
$\therefore\ 5\text{kg }5\text{g}$
$=5.005\ kg$

The decimal which should be subtracted from $0.1$ to get $0.06$ can be obtained by subtracting $0.06$ from $0.1$
Converting given decimals into like decimals, we have $0.10$ and $0.06$
Now,
$= 0.10 - 0.06$
$= 0.04$
$\therefore$ Required decimal $= 0.1 - 0.06$
$= 0.04$

The given decimal is $1.04$
$=1.04$
$=1+0.04$
$=1+\frac{4}{100}$
$=1+\frac{4\div4}{100\div4}$
$=1+\frac{1}{25}$
$=1\frac{1}{25}$

We know that,
$1\text{ml}=\frac{1}{1000}\text{l}$
$\therefore\ 8\text{ml}=\frac{8}{1000}\text{l}$
$=0.008\text{l}$

It is given that,
$14 \times 4 = 56$
Now, $0.014$ has $3$ decimal places.
So, the required product must contain $3$ places of decimals.
$\therefore 0.014 \times 4 = 0.056$

$=0.002\times0.5$
$=\frac{2}{1000}\times\frac{5}{10}$
$=\frac{2\times5}{1000\times10}$
$=\frac{10}{10000}$
$=\frac{1}{1000}$
$=0.01$

The given fraction is $2\frac{1}{25}.$ Now,
$=2\frac{1}{25}$
$=2+\frac{1}{25}$
$=2+\frac{1\times4}{25\times4}$
$=2+\frac{4}{100}$
$=2+0.04$
$=2.04$

The decimal number which should be added to $5.09$ to get $5.5$ is obtained by subtracting $5.09$ from $5.5$
Converting the given decimals to like decimals, we have $5.09$ and $5.50$
Now,
$= 5.50 - 5.09$
$= 0.41$
$\therefore$ Required decimal $= 5.50 - 5.09 = 0.41$
Thus, $0.41$ must be added to $5.09$ to get $5.5$

We have,
$3 \times 3 \times 3 = 27$
The sum of the decimal places in the given decimals is $1 + 1 + 1 = 3$
So, the product must contain $3$ places of decimals.
$\therefore 0.3 \times 0.3 \times 0.3 = 0.027$

In order to find the product, we first multiply $8$ by $25$
We have, $25 \times 8 = 200$
Now, $0.25$ has $2$ decimal places and $0.8$ has $1$ decimal place.
The sum of the decimal places is $2 + 1 = 3$
So, the product must contain $3$ places of decimals.
$\therefore\ 0.25\times0.8$
$=0.200$
$=0.2$

$=75.57\div0.01$
$=\frac{75.57}{0.01}$
$=\frac{75.57\times100}{0.01\times100} ($Multiply numerator and denominator by $100$ to convert the divisor$)$
$=\frac{7557}{1}$
$=7557$

$=0.012\div1.5$
$=\frac{0.012}{1.5}$
$=\frac{0.012\times10}{1.5\times10} ($Multiply the numberator and denominator by $10$ to convert the divison$)$
$=\frac{0.12}{15}$

$\therefore\ 0.012\div1.5=0.008$