4 Mark Question

Question 14 Marks

A coin is tossed 300 times and we get head : 136 times and tail : 164 times.
When a coin is tossed at random, What is the probability of getting (i) a head, (ii) a tail?

Answer

Total number of trials = 300
Number of times a head is obtained = 136
Number of times a tail is obtained = 164

Probability of getting head$=\frac{\text{Number of times heads is obtained}}{\text{Total number of trials}}=\frac{136}{300}=\frac{34}{75}$
Probability of getting tail$=\frac{\text{Number of times tails is obtained}}{\text{Total number of trials}}=\frac{164}{300}=\frac{41}{75}$

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Question 24 Marks

Two coins are tossed simultaneously 200 times and we get two heads: 58 times, one head: 83 times: 0 head: 59 times.
When two coins are tossed at random, what is the probability of getting (i) 2 heads, (ii) 1 head, (iii) 0 head?

Answer

Total number of trials = 200
Number of times 2 heads are obtained = 58
Number of times one head is obtained = 83
Number of times no head is obtained = 59

Probability of getting 2 heads $=\frac{\text{Number of times 2 heads have been obtained}}{\text{Total number of trials}}=\frac{58}{200}=\frac{29}{100}$
Probability of getting 1 head $=\frac{\text{Number of times 1 head has been obtained}}{\text{Total number of trials}}=\frac{83}{200}$
Probability of getting 0 head $=\frac{\text{Number of times head has not been obtained}}{\text{Total number of trials}}=\frac{59}{200}$

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Question 34 Marks

A dice is thrown 100 times and the outcomes are noted as given below:

Outcome	1	2	3	4	5	6
Frequency	21	14	18	15	23	9

When a dice is thrown at random, what is the probability of getting a (i) 3, (ii) 6, (iii) 6, (iv) 1?

Answer

Total number of trials = 100
Number of times 3 is obtained = 18
Number of times 6 is obtained = 9
Number of times 4 is obtained = 15
Number of times 1 is obtained = 21

Probability of getting a 3 $=\frac{\text{Number of times 3 is obtained}}{\text{Total number of trials}}=\frac{18}{100}=\frac{9}{50}$
Probability of getting a 6 $=\frac{\text{Number of times 6 is obtained}}{\text{Total number of trials}}=\frac{9}{100}$
Probability of getting a 4 $=\frac{\text{Number of times 4 is obtained}}{\text{Total number of trials}}=\frac{15}{100}=\frac{3}{20}$
Probability of getting a 1 $=\frac{\text{Number of times 1 is obtained}}{\text{Total number of trials}}=\frac{21}{100}$

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Maths 4 Mark Question

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