If in $\text{a}\triangle\text{ABC},\tan\text{B}+\tan\text{C}=6,$ then $\cot\text{A}\cot\text{B}\cot\text{C}=$
View full solution →- $6$
- $1$
- $\frac16$
- None of these
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M.C.Q (1 Marks)
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$\tan{\text{(A+B)}}$
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