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Herons Formula MATHS - Herons Formula

Rajasthan Board (RBSE) - STD 9 - MATHS (Rajasthan - English Medium). 49 questions in this chapter.

Question types

Herons Formula question types

49 questions across 5 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.

49
Questions
5
Question groups
5
Question types
Sample Questions

Herons Formula questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1M.C.Q1 Mark
A square and an equilateral triangle have equal perimeters. If the diagonal of the square is $12\sqrt{2}\text{cm},$ then area of the triangle is:
  1. $24\sqrt{2}\text{cm}^2$
  2. $24\sqrt{3}\text{cm}^2$
  3. $48\sqrt{3}\text{cm}^2$
  4. $64\sqrt{3}\text{cm}^2$
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Q 2M.C.Q1 Mark
The sides of a triangle are 11m, 60m and 61m. The altitude to the smallest side is:
  1. 11cm
  2. 66cm
  3. 50cm
  4. 60cm
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Q 3M.C.Q1 Mark
The length of each side of an equilateral triangle of area $4\sqrt{3}\text{ cm}^2,$ is:
  • ✓
    $4\text{ cm}$
  • B
    $\frac{4}{\sqrt{3}}\text{ cm}$
  • C
    $\frac{\sqrt{3}}{4}\text{ cm}$
  • D
    $3\text{ cm}$

Answer: A.

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Q 4M.C.Q1 Mark
If every side of a triangle is doubled, then increase in the area of the triangle is:
  1. $100\sqrt{2}\%$
  2. $200\%$
  3. $300\%$
  4. $400\%$
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Q 5M.C.Q1 Mark
The sides of a triangle are 7cm, 9cm and 14cm. Its area is:
  1. $12\sqrt{5}\text{cm}^2$
  2. $12\sqrt{3}\text{cm}^2$
  3. $24\sqrt{5}\text{cm}^2$
  4. $63\text{cm}^2$
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Q 144 Marks Questions4 Marks
The lengths of the sides of a triangle are in a ratio of $3 : 4 : 5$ and its perimeter is $144\ cm.$ Find the area of the triangle and the height corresponding to the longest side.
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