Question 14 Marks
The force exerted to pull a cart is directly proportional to the acceleration produced in the body. Express the statement as a linear equation of two variables and draw the graph of the same by taking the constant mass equal to $6 \ kg$. Read from the graph, the force required when the acceleration produced is:
- $5ms^{-2}$
- $6ms^{-2}$
Answer
View full question & answer→Given that, the force $(F)$ is directly proportional to the the acceleration $(a) i.e. \text{F}\propto\text{a}$
$\Rightarrow\text{F}=\text{ma} [$where $m =$ arbitary constant and take value $6\ kg$ of mass$]$ $\therefore\text{F}=6\text{a}$
Here, we find two points $A(5, 30)$ and $B(6, 36).$
So draw the graph by plotting the point and joining the line $AB.$
$\Rightarrow\text{F}=\text{ma} [$where $m =$ arbitary constant and take value $6\ kg$ of mass$]$ $\therefore\text{F}=6\text{a}$
- If $\text{a}=5\frac{\text{m}}{\text{s}}^2$ then from $Eq\ (i),$ we get
- If $\text{a}=6\frac{\text{m}}{\text{s}}^2$ then from $Eq\ (i),$ we get
Here, we find two points $A(5, 30)$ and $B(6, 36).$
So draw the graph by plotting the point and joining the line $AB.$
