Question types

Quadrilaterals question types

57 questions across 5 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.

57
Questions
5
Question groups
5
Question types
Sample Questions

Quadrilaterals questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1M.C.Q1 Mark
Write the correct answer in the following:
A diagonal of a rectangle is inclined to one side of the rectangle at 25º. The acute angle between the diagonals is:
  1. 55º
  2. 50º
  3. 40º
  4. 25º
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Q 2M.C.Q1 Mark
Write the correct answer in the following:
If bisectors of $\angle \text{A}$ and $\angle \text{B}$ of a quadrilateral ABCD intersect each other at P, of $\angle \text{B}$ and $\angle \text{C}$ at Q, of $\angle \text{C}$ and $\angle \text{D}$ at R and of $\angle \text{D}$ and $\angle \text{A}$ at S, then PQRS is a:
  1. Rectangle.
  2. Rhombus.
  3. Parallelogram.
  4. Quadrilateral whose opposite angles are supplementary.
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Q 3M.C.Q1 Mark
Write the correct answer in the following:
If APB and CQD are two parallel lines, then the bisectors of the angles APQ, BPQ, CQP and PQD form:
  1. A square.
  2. A rhombus.
  3. A rectangle.
  4. Any other parallelogram.
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Q 4M.C.Q1 Mark
Write the correct answer in the following:
The quadrilateral formed by joining the mid-points of the sides of a quadrilateral PQRS, taken in order, is a rhombus, if:
  1. PQRS is a rhombus.
  2. PQRS is a parallelogram.
  3. Diagonals of PQRS are perpendicular.
  4. Diagonals of PQRS are equal.
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Q 5M.C.Q1 Mark
Write the correct answer in the following:
If angles A, B, C and D of the quadrilateral ABCD, taken in order, are in the ratio 3 : 7 : 6 : 4, then ABCD is a:
  1. Rhombus.
  2. Parallelogram.
  3. Trapezium.
  4. Kite.
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D, E and F are the mid-points of the sides BC, CA and AB, respectively of an equilateral triangle ABC. Show that $\Delta\text{DEF}$ is also an equilateral triangle.
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E and F are respectively the mid-points of the non-parallel sides AD and BC of a trapezium ABCD. Prove that EF || AB and$\text{EF}=\frac{1}{2}(\text{AB}=\text{CD})$
[Hint: Join BE and produce it to meet CD produced at G.]
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