MCQ 11 Mark
A body is projected vertically upward with the velocity $y=3 \hat{i}+4 \hat{j} ms ^{-1}$. The maximum height attained by the body is $\left( g =10\ ms ^{-2}\right)$.
- A$7 m$
- ✓$1.25 m$
- C$8 m$
- D$0.08 m$
Answer
View full question & answer→Correct option: B.
$1.25 m$
$v =3 \hat{i}+4 \hat{j} $
$ H _{\max }=\frac{v^2 \sin ^2 \theta}{2 g}=\frac{v^2}{2 g}[\theta=90] $
$ v =\sqrt{9+16}=\sqrt{25} $
$ v ^2=25 $
$ H _{\max }=\frac{25}{20}=\frac{5}{4}=1.25 m $
$ H _{\max }=\frac{v^2 \sin ^2 \theta}{2 g}=\frac{v^2}{2 g}[\theta=90] $
$ v =\sqrt{9+16}=\sqrt{25} $
$ v ^2=25 $
$ H _{\max }=\frac{25}{20}=\frac{5}{4}=1.25 m $





















