MCQ
$1$-butyne can be distinguished from $2$-butyne by
- A$H_2/Pd\ BaSO_4$
- B$Br_2 / H_2O$
- ✓$Cu_2Cl_2/NH_4OH$
- DBayer's reagent
✓
Answer
Correct option: C.
$Cu_2Cl_2/NH_4OH$
c
$C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\xrightarrow{C{{u}_{2}}C{{l}_{2}}/N{{H}_{4}}OH}$
$C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\xrightarrow{C{{u}_{2}}C{{l}_{2}}/N{{H}_{4}}OH}$
$C{{H}_{3}}-C{{H}_{2}}-C\equiv \overset{\Theta }{\mathop{C}}\,\,\overset{\oplus }{\mathop{C}}\,u\,\,(\operatorname{Re}d\,Coloured)$
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