MCQ
$1.24\, gm \,P $ is present in $2.2\, gm$
- ✓${P_4}{S_3}$
- B${P_2}{S_2}$
- C$P{S_2}$
- D${P_2}{S_4}$
✓
Answer
Correct option: A.
${P_4}{S_3}$
a
(a) Choice $(a)$ is ${P_4}{S_3}$ $\frac{{31 \times 4}}{{(124)}}\,gm $ $P$ is present in $220\,gm$ ${P_4}{S_3}$
(a) Choice $(a)$ is ${P_4}{S_3}$ $\frac{{31 \times 4}}{{(124)}}\,gm $ $P$ is present in $220\,gm$ ${P_4}{S_3}$
$\therefore $ $1.24\,gm$ $P$ is present in = $\frac{{220}}{{124}} \times 1.24 = 2.2\,gm$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Characteristics of above reaction is
An enantiomerically pure acid is treated with racemic mixture of an alcohol having one chiral carbon. The ester formed will be
When $CHCl_3$ is boiled with $NaOH$ , It gives
→The crystal field splitting energy for octahedral $\left( {{\Delta _0}} \right)$ and tetrahedral $\left( {{\Delta _t}} \right)$ complexes is related as
→Which of the following reagents will convert propionic acid to $1-$ propanol
→Name the compound, that is not isomer with diethyl ether
The absolute configuration of the compound is
How many total oximes are possible for ketons having molecular formula $C_3H_6O$,$C_4H_8O$ and $C_5H_{10}O$
→Some standard electrode potentials at $298 K$ are given below:
→| $Pb ^{2+} / Pb$ | $-0.13 V$ |
| $Ni ^{2+} / Ni$ | $-0.24 V$ |
| $Cd ^{2+} / Cd$ | $-0.40 V$ |
| $Fe ^{2+} / Fe$ | $V-0.44 V$ |
To a solution containing $0.001 M$ of $X ^{2+}$ and $0.1 M$ of $Y ^{2+}$, the metal rods $X$ and $Y$ are inserted (at $298 K$ ) and connected by a conducting wire. This resulted in dissolution of $X$. The correct combination(s) of $X$ and $Y$, respectively, is (are)
(Given: Gas constant, $R =8.314 J K ^{-1} mol ^{-1}$,
Faraday constant, $F =96500 C mol ^{-1}$ )
$(A)$ $Cd$ and $Ni$ $(B)$ $Cd$ and $Fe$ $(C)$ $Ni$ and $Pb$ $(D)$ $Ni$ and $Fe$
If $HCl$ molecule is completely polarized, so expected value of dipole moment is $6.12\,D \,(deby),$ but experimental value of dipole moment is $1.03\,D.$ Calculate the percentage ionic character
→