MCQ
$1.24\, gm \,P $ is present in $2.2\, gm$
  • ${P_4}{S_3}$
  • B
    ${P_2}{S_2}$
  • C
    $P{S_2}$
  • D
    ${P_2}{S_4}$

Answer

Correct option: A.
${P_4}{S_3}$
a
(a) Choice $(a)$ is ${P_4}{S_3}$ $\frac{{31 \times 4}}{{(124)}}\,gm $ $P$ is present in $220\,gm$ ${P_4}{S_3}$

$\therefore $ $1.24\,gm$ $P$ is present in = $\frac{{220}}{{124}} \times 1.24 = 2.2\,gm$

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