13 (y-4) -3 (y-9)-5(y+4)=0 - Vidyadip

Question

$13 (\text{y}-4) -3 (\text{y}-9)-5(\text{y}+4)=0$

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Answer

$13 (\text{y}-4) -3 (\text{y}-9)-5(\text{y}+4)=0$ $\Rightarrow13\text{y}-52-3\text{y+27}-5\text{y}-20=0$ $\Rightarrow13\text{y}-3\text{y}-5\text{y}-52+27-20=0$ $\Rightarrow13\text{y}-8\text{y}-72+27=0$ $\Rightarrow5\text{y - 45 = 0}$ Dividing by 5, $\text{y}=9$Verification:
$\text{L.H.S.}=13(\text{y} - 4)-3(\text{y} - 9) - 5 (\text{y}+4)$ $=13(9-4)-3(9-9)-5(9+4)$ $=13\times5-3\times0-5\times13$ $=65-0-65$ $=0$ $=\text{R.H.S.}$

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