Question
It is given that the length of the rectangular piece is 20 m and its width is 15 m .And, from each corner a quadrant each of radius 3.5 m has been cut out. A rough figure for this is given below:
✓
Answer
Length of rectangular portion $( l )=20 m$
breadth (b) $=15 m$
Area of the rectangular piece $=1 \times b=20 \times 15=300 m^2$
Radius of semicircular portion $(r)=3.5 m$
Total area of 4 quadrants
$=4\times\frac{1}{4}\times\pi\text{r}^2=\frac{22}{7}\times(3.5)^2\text{m}^2$
$=\frac{22}{7}\times12.25\text{m}^2=22\times1.75\text{m}^2=38.5\text{m}^2$
breadth (b) $=15 m$
Area of the rectangular piece $=1 \times b=20 \times 15=300 m^2$
Radius of semicircular portion $(r)=3.5 m$
Total area of 4 quadrants
$=4\times\frac{1}{4}\times\pi\text{r}^2=\frac{22}{7}\times(3.5)^2\text{m}^2$
$=\frac{22}{7}\times12.25\text{m}^2=22\times1.75\text{m}^2=38.5\text{m}^2$
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