MCQ
$1\,\,M$ of $10 \,ml$ ${H_2}S{O_4}$ will completely neutralise
- A$10\,\,ml$ of $1\,\,M\,\,NaOH$ solution
- ✓$10\,\,ml$ of $2\,\,M\,\,NaOH$ solution
- C$5\,\,ml$ of $2\,\,M\,\,KOH$ solution
- D$5\,\,ml$ of $1\,\,M\,\,N{a_2}C{O_3}$ solution
✓
Answer
Correct option: B.
$10\,\,ml$ of $2\,\,M\,\,NaOH$ solution
(b) ${H_2}S{O_4} + 2{H_2}O$ $ \rightleftharpoons $ $2{H_3}{O^ + } + SO_4^{ - \, - }$
$NaOH$ $ \rightleftharpoons $ $N{a^ + } + O{H^ - }$
$1$ mole of ${H_2}S{O_4}$ acid gives $2$ moles of ${H_3}{O^ + }$ ions. So $2$ moles of $O{H^ - }$ are required for complete neutralization.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In which of the following half cells, electrochemical reaction is pH dependent?
The binaphthol $(Bnp)$ is
→Concentration of $H^+$ ions in $10^{-4}\,M\,HCl$ solution is
→An aqueous solution of hydrazine $\left( N _2 H _4\right)$ is electrochemically oxidized by $O _2$, thereby releasing chemical energy in the form of electrical energy. One of the products generated from the electrochemical reaction is $N _2( g )$.Choose the correct statement($s$) about the above process
$(A)$ $OH ^{-}$ions react with $N _2 H _4$ at the anode to form $N _2( g )$ and water, releasing $4$ electrons to the anode.
$(B)$ At the cathode, $N _2 H _4$ breaks to $N _2( g )$ and nascent hydrogen released at the electrode reacts with oxygen to form water.
$(C)$ At the cathode, molecular oxygen gets converted to $OH ^{-}$.
$(D)$ Oxides of nitrogen are major by$-$products of the electrochemical process.
→$(A)$ $OH ^{-}$ions react with $N _2 H _4$ at the anode to form $N _2( g )$ and water, releasing $4$ electrons to the anode.
$(B)$ At the cathode, $N _2 H _4$ breaks to $N _2( g )$ and nascent hydrogen released at the electrode reacts with oxygen to form water.
$(C)$ At the cathode, molecular oxygen gets converted to $OH ^{-}$.
$(D)$ Oxides of nitrogen are major by$-$products of the electrochemical process.
The strongest acid among the following compounds is
Here are possible synthesis of phenylpropyl ether. Which one would work ?
In benzene molecule all $C - C$ bond lengths are equal because
→Hex$-4-$ene$-2-$ol on treatment with $PCC$ gives $'A'.$
→$'A'$ on reaction with sodium hypoiodite gives $'B',$ which on further heating with soda lime gives ' $C$ '. The compound ' $C$ ' is $....... .$
Consider on following molecules $NH_3, PH_3, AsH_3, SbH_3$ Which of the following has the highest boiling point
→Chlorine is used in water for