Question
$8 g$ of $He$ is equal to:
$8g$ of he $= 2$ moles of He aprox $(1$ mole of he $= 4.003g)$
$= 2 \times 6.0221 \times 10^{23}$
$(1$ mole is amount of substance that contains avogadro no. of particles$)$
$= 12.0442 \times 10^{23}$atoms.
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