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STD 12 - 3. Chemical kinetics — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 3. Chemical kinetics4 Marks
MCQ
$A + 2B \to 3C$ for the chemical reaction
  • A
    $ - \frac{{d[A]}}{{dt}} =  - \frac{1}{2}\frac{{d[B]}}{{dt}} =  - \frac{1}{3}\frac{{d[C]}}{{dt}}$
  • ✓
    $ - \frac{{d[A]}}{{dt}} =  - \frac{1}{2}\frac{{d[B]}}{{dt}} = \frac{1}{3}\frac{{d[C]}}{{dt}}$
  • C
    $\frac{{d[A]}}{{dt}} = \frac{1}{2}\frac{{d[B]}}{{dt}} = \frac{1}{3}\frac{{d[C]}}{{dt}}$
  • D
    $ - \frac{{d[A]}}{{dt}} = 2\frac{{d[B]}}{{dt}} = 3\frac{{d[C]}}{{dt}}$
✓

Answer

Correct option: B.
$ - \frac{{d[A]}}{{dt}} =  - \frac{1}{2}\frac{{d[B]}}{{dt}} = \frac{1}{3}\frac{{d[C]}}{{dt}}$
b

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