A $3\, volt$ battery with negligible internal resistance is connected in a circuit as shown in the figure. The current $I$, in the circuit will be ............. $A$
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A battery of $3.0\, V$ is connected to a resistor dissipating $0.5\, W$ of power. If the terminal voltage of the battery is $2.5\, V$ the power dissipated within the internal resistance is$.......W$
Two cells when connected in series are balanced on $8\;m$ on a potentiometer. If the cells are connected with polarities of one of the cell is reversed, they balance on $2\,m$. The ratio of $e.m.f.$'s of the two cells is
A potentiometer wire of length $L$ and a resistance $r$ are connected in series with a battery of e.m.f. $E_0$ and a resistance $r_1$. An unknown e.m.f. $E$ is balanced at a length $l$ of the potentiometer wire. The e.m.f. $E$ will be given by
In the circuit shown the resistance of voltmeter is $10,000\, ohm$ and that of ammeter is $20\,ohm$. The ammeter reading is $0.10\,Amp$ and voltmeter reading is $12$ $\mathrm{volt}.$ Then $R$ is equal to .............. $\Omega$
In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given $R_1 = 15\,\Omega $$,R _2 = 10\,\Omega ,$$ R_3 = 20\,\Omega ,$$ R_4 = 5\,\Omega ,$$R_5 = 25\,\Omega ,$$R_6 = 30\,\Omega , $$E = 15\,V$