MCQ
A box contains 10 good articles and 6 with defects. One item is drawn at random. The probability that it is either good or has a defect is,
- A$\frac{64}{64}$
- B$\frac{49}{64}$
- C$\frac{40}{64}$
- D$\frac{24}{64}$
Solution:
P(good item) $=\frac{10}{16}$
P(defected item) $=\frac{6}{16}$
P(eitherr good or defected item) = P(good item) + P(defected item)
$=\frac{10}{16}+\frac{6}{16}$
$=\frac{16}{16}$
$=1$
$=\frac{64}{64}$
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