MCQ
A capacitor of capacity $C$ has reactance $X$. If capacitance and frequency become double then reactance will be
- A$2X$
- B$4X$
- C$X/2$
- ✓$X/4$
✓
Answer
Correct option: D.
$X/4$
d
$X=\frac{1}{C \omega} \quad X^{\prime}=\frac{1}{4 C \omega}$
$X=\frac{1}{C \omega} \quad X^{\prime}=\frac{1}{4 C \omega}$
$X^{\prime}=\frac{X}{4}$
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