Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsThermodynamics3 Marks
Question
A Carnot refrigerator operates between 250K and 300K. Calculate its coefficient of performance.
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Answer
Data: $T _{ C }=250 K _{,} T _{ H }=300 K$ $ K =\frac{T_{ C }}{T_{ H }-T_{ C }}=\frac{250 K }{300 K -250 K }=\frac{250}{50}=5 $ This is the coefficient of performance of the refrigerator.
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