MCQ
A closed pipe and an open pipe have their first overtones identical in frequency. Their lengths are in the ratio
- A$1:2$
- B$2:3$
- ✓$3:4$
- D$4:5$
$\Rightarrow$$3\left( {\frac{v}{{4{l_1}}}} \right) = 2\left( {\frac{v}{{2{l_2}}}} \right)$;
where $l_1$ and $l_2$ are the lengths of closed and open organ pipes
hence $\frac{{{l_1}}}{{{l_2}}} = \frac{3}{4}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


