Question
A collision experiment is done on a horizontal table kept in an elevator. Do you expect a change in the results if the elevator is accelerated up or down because of the noninertial character of the frame?
✓
Answer
Velocity and mass are only two components that affect collision between two bodies so in this change in acceleration due to gravity will not affect the collision between two bodies. (if kept horizontally)
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Coulomb's law states that the electrostatic force of attraction or repulsion acting between two stationary point charges is given by
where F denotes the force between two charges $q _1$ and $q _2$ separated by a distance r in free space, $\varepsilon_0$ is a constant known as the permittivity of free space. Free space is a vacuum and may be taken to be air practically. If free space is replaced by a medium, then $\varepsilon_0$ is replaced by $\left(\varepsilon_0 k\right)$ or $\left(\varepsilon_0 \varepsilon_r\right)$ where k is known as dielectric constant or relative permittivity.
(i) In coulomb's law, $F =k \frac{q_1 q_2}{r^2}$, then on which of the following factors does the proportionality constant k depends?
(a) Nature of the medium between the two charges
(b) Distance between the two charges
(c) Electrostatic force acting between the two charges
(d) Magnitude of the two charges
(ii) Dimensional formula for the permittivity constant $\varepsilon_0$ of free space is
(a) $\left[ M ^{-1} L^3 T^2 A^2\right]$
(b) $\left[ ML ^{-3} T^4 A^2\right]$
(c) $\left[ M ^{-1} L^{-3} T^4 A^2\right]$
(d) $\left[ ML ^{-3} T^4 A^{-2}\right]$
(iii) The force of repulsion between two charges of 1 C each, kept 1m apart in vaccum is
(a) $\frac{1}{9 \times 10^9} N$
(b) $\frac{1}{9 \times 10^{12}} N$
(c) $9 \times 10^7 N$
(d) $9 \times 10^9 N$
(iv) Two identical charges repel each other with a force equal to 10 mgwt when they are 0.6 m apart in air. ( $g =$ $10 m s ^{-2}$ ). The value of each charge is
(a) 2 mC
(b) $2 \times 10^{-7} mC$
(c) $2 \mu C$
(d) 2 nC
OR
Coulomb's law for the force between electric charges most closely resembles with
(a) law of conservation of energy
(b) Newton's 2nd law of motion
(c) law of conservation of charge .
(d) Newton's law of gravitation
→where F denotes the force between two charges $q _1$ and $q _2$ separated by a distance r in free space, $\varepsilon_0$ is a constant known as the permittivity of free space. Free space is a vacuum and may be taken to be air practically. If free space is replaced by a medium, then $\varepsilon_0$ is replaced by $\left(\varepsilon_0 k\right)$ or $\left(\varepsilon_0 \varepsilon_r\right)$ where k is known as dielectric constant or relative permittivity.
(i) In coulomb's law, $F =k \frac{q_1 q_2}{r^2}$, then on which of the following factors does the proportionality constant k depends?
(a) Nature of the medium between the two charges
(b) Distance between the two charges
(c) Electrostatic force acting between the two charges
(d) Magnitude of the two charges
(ii) Dimensional formula for the permittivity constant $\varepsilon_0$ of free space is
(a) $\left[ M ^{-1} L^3 T^2 A^2\right]$
(b) $\left[ ML ^{-3} T^4 A^2\right]$
(c) $\left[ M ^{-1} L^{-3} T^4 A^2\right]$
(d) $\left[ ML ^{-3} T^4 A^{-2}\right]$
(iii) The force of repulsion between two charges of 1 C each, kept 1m apart in vaccum is
(a) $\frac{1}{9 \times 10^9} N$
(b) $\frac{1}{9 \times 10^{12}} N$
(c) $9 \times 10^7 N$
(d) $9 \times 10^9 N$
(iv) Two identical charges repel each other with a force equal to 10 mgwt when they are 0.6 m apart in air. ( $g =$ $10 m s ^{-2}$ ). The value of each charge is
(a) 2 mC
(b) $2 \times 10^{-7} mC$
(c) $2 \mu C$
(d) 2 nC
OR
Coulomb's law for the force between electric charges most closely resembles with
(a) law of conservation of energy
(b) Newton's 2nd law of motion
(c) law of conservation of charge .
(d) Newton's law of gravitation
A charged particle moving in a magnetic field experiences a force that is proportional to the strength of the magnetic field, the component of the velocity that is perpendicular to the magnetic field and the charge of the particle. This force is given by $\vec{\text{F}}=\text{q}(\vec{\text{v}}\times\vec{\text{B}})$ where q is the electric charge of the particle, v is the instantaneous velocity of the particle, and Bis the magnetic field (in tesla). The direction of force is determined by the rules of cross product of two vectors. Force is perpendicular to both velocity and magnetic field. Its direction is same as $\vec{\text{v}}\times\vec{\text{B}}$ if q is positive and opposite of $\vec{\text{v}}\times\vec{\text{B}}$ if q is negative. The force is always perpendicular to both the velocity of the particle and the magnetic field that created it. Because the magnetic force is always perpendicular to the motion, the magnetic field can do no work on an isolated charge. It can only do work indirectly, via the electric field generated by a changing magnetic field.
→
- When a magnetic field is applied on a stationary electron, it:
- Remains stationary.
- Spins about its own axis.
- Moves in the direction of the field.
- Moves perpendicular to the direction of the field.
- A proton is projected with a uniform velocity v along the axis of a current carrying solenoid, then,
- The proton will be accelerated along the axis.
- The proton path will be circular about the axis.
- The proton moves along helical path.
- The proton will continue to move with velocity v along the axis.
- A charged particle experiences magnetic force in the presence of magnetic field. Which of the following statement is correct?
- The particle is stationary and magnetic field is perpendicular.
- The particle is moving and magnetic field is perpendicular to the velocity.
- The particle is stationary and magnetic field is parallel.
- The particle is moving and magnetic field is parallel to velocity.
- A charge q moves with a velocity 2m s-1 along x-axis in a uniform magnetic field $\vec{\text{F}}=(\vec{\text{i}}+2\vec{\text{j}}+3\vec{\text{k}})\text{T,}$ charge will experience a force.
- In z-y plane.
- Along -y axis.
- Along +z axis.
- Along -z axis.
- Moving charge will produce.
- Electric field only.
- Magnetic field only.
- Both electric and magnetic field.
- None of these.
A small coin is placed on a record rotating at $33\frac{1}{3}$ rev/ minute. The coin does not slip on the record. Where does it get the required centripetal force from?
→Establish the relation between mean value and peak value of AC.
Out of the two magnetic materials, 'A' has relative permeability slightly greater than unity while oB' has less than unity. Identify the nature of the materials 'A' and 'B'. Will their susceptibilities be positive or negative?
The power averaged over one full cycle of a.c. is known as average power. It is also known as true power.
$\text{P}_\text{av}=\text{V}_\text{rms}\text{I}_\text{rms}\cos\phi=\frac{\text{V}_0\text{I}_0}{2}\cos\phi$
Root mean square or simply rms watts refer to continuous power.
A circuit containing a 80mH inductor and a $60\mu\text{F}$ capacitor in series is connected to a 230V, 50Hz supply. The resistance of the circuit is negligible.
→$\text{P}_\text{av}=\text{V}_\text{rms}\text{I}_\text{rms}\cos\phi=\frac{\text{V}_0\text{I}_0}{2}\cos\phi$
Root mean square or simply rms watts refer to continuous power.
A circuit containing a 80mH inductor and a $60\mu\text{F}$ capacitor in series is connected to a 230V, 50Hz supply. The resistance of the circuit is negligible.
- The value of current amplitude is:
- 15A
- 11.63A
- 17.65A
- 6.33A
- Find rms value.
- 6A
- 5.25A
- 8.23A
- 7.52A
- The average power transferred to inductor is:
- Zero
- 7W
- 2.5W
- 5W
- The average power transferred to the capacitor is:
- 5W
- Zero
- 11W
- 15W
- What is the total average power absorbed by the circuit?
- Zero
- 10W
- 2.5W
- 15W
When light from a monochromatic source is incident on a single narrow slit, it gets diffracted and a pattern of ahem ate bright and dark fringes is obtained on screen, called "Diffraction Pattern" of single slit. ln diffraction pattern of single slit, it is found that.
→→- Central bright fringe is of maximum intensity and the intensity of any secondary bright fringe decreases with increase in its order.
- Central bright fringe is twice as wide as any other secondary bright or dark fringe.
- A single slit of width 0.1mm is illuminated by a parallel beam oftight of wavelength $6000\mathring{\text{A}}$ and diffraction bands are observed on a screen 0.5m from the slit. The distance of the third dark band from the central bright band is:
- 3mm
- 1.5mm
- 9mm
- 4.5mm
- ln Fraunhofer diffraction pattern, slit width is 0.2mm and screen is at 2m away from the lens. If wavelength of tight used is $5000\mathring{\text{A}}$ then the distance between the first minimum on either side the central maximum is:
- 10-1m
- 10-2m
- 2 × 10-2m
- 2 × 10-1m
- Light of wavelength 600nm is incident normally on a slit of width 0.2mm. The angular width of central maxima in the diffraction pattern is (measured from minimum to minimum).
- 6 × 10-3rad
- 4 × 10-3rad
- 2.4 × 10-3rad
- 4.5 × 10-3rad
- A diffraction pattem is obtained by using a beam of red light. What will happen, if the red light is replaced by the blue light?
- Bands disappear
- Bands become broader and farther apart
- No change will take place
- Diffraction bands become narrower and crowded together.
- To observe diffraction, the size of the obstacle.
- Should be $\frac{\lambda}{2}$, where $\lambda$, is the wavelength.
- Should be of the order of wavelength.
- Has no relation to wavelength.
- Should be much larger than the wavelength.
You are holding a cage containing a bird. Do you have to make less effort if the bird flies from its position in the cage and manages to stay in the middle without touching the walls of the cage? Does it make a difference whether the cage is completely closed or it has rods to let air pass?