MCQ
A complex containing $K^+, Pt(IV)$ and $Cl^-$ is $100\%$ ionised giving $i = 3$. Thus, possible complex is
- A$K_2[Pt\, Cl_4]$
- ✓$K_2[Pt\, Cl_6]$
- C$K_3[Pt\, Cl_5]$
- D$K[Pt\, Cl_3]$
(2) $K _{2} P t Cl _{6} \rightarrow 2 K ^{+}+\left[ P _{ t } Cl _{6}\right]^{2-} ; i =1+2=3$
In $(1)$, oxidation number of $Pt =2$
In $(2),$ the oxidation number of $P t=4$
Therefore, $K _{2}\left[ P t Cl _{6}\right]$ is the correct answer.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
In which case the value of $\Delta H_{sol.} < 0$
$(I)$ cis $- [Co(NH_3)_2(en)_2]^{3+}$ $(II)$ trans $-[IrCl_2(C_2O_4)_2]^{3-}$
$(III)\, [Rh(en)_3]^{3+}$ $(IV)$ cis $-[Ir(H_2O)_3Cl_3$
$\begin{array}{*{20}{c}}
H\\
|\\
{ClHC = HC - C - CH = CHCl}\\
|\\
{Cl}
\end{array}$