MCQ
A dynamo develops 0.5A at 6V.The energy which is generated in one second is:
- A0.083J
- B3J
- C12J
- Dnone of these
Explanation:
Voltage(V) = 6V
Current(I) = 0.5A
Time(t) = 1sec
Energy generated = VIt
⇒ Energy = 6 × 0.5 × 1 = 3J
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R = f
R = 2
$\text{R}=\frac{\text{f}}{2}$
R = 3f