A group of $N$ cells whose $emf$ varies directly with the internal resistance as per the equation $E_N = 1.5\, r_N$ are connected as shown in the figure below. The current $I$ in the circuit is ........... $amp$
Medium
Download our app for free and get startedPlay store
$i = \frac{{{E_1} + {E_2} + {E_3} + ..... + {E_n}}}{{({r_1} + {r_2} + {r_3} + ....... + {r_n})}}$

$ = \frac{{1.5({r_1} + {r_2} + {r_3} + ...... + {r_n})}}{{({r_1} + {r_2} + {r_3} + ..... + {r_n})}} = 1.5\,A$.

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    In the figure shown, if the internal resistance of the battery is $1\, ohm$ , the reading of the ammeter will be ................. $\mathrm{A}$
    View Solution
  • 2
    Assertion : Bending a wire does not effect electrical resistance.

    Reason : Resistance of wire is proportional ot resistivity of material.

    View Solution
  • 3
    A null point is found at $200\,cm$ in potentiometer when cell in secondary circuit is shunted by $5\,\Omega$. When a resistance of $15\,\Omega$ is used for shunting null point moves to $300\,cm$. The internal resistance of the cell is $..............\,\Omega$.
    View Solution
  • 4
    By a cell a current of $0.9\, A$ flows through $2\, ohm$ resistor and $0.3\,A$ through $7\, ohm$ resistor. The internal resistance of the cell is ............ $\Omega$
    View Solution
  • 5
    For the circuit shown, with ${R_1} = 1.0\,\Omega $, ${R_2} = 2.0\,\Omega $, ${E_1} = 2\,V$ and ${E_2} = {E_3} = 4\,V$, the potential difference between the points $‘a’$ and $‘b’$ is approximately (in $V$)
    View Solution
  • 6
    A steady current $I$ is set up in a wire whose cross-sectional area decreases in the direction of the flow of the current. Then, as we examine the narrowing region,
    View Solution
  • 7
    The length of a given cylindrical wire is increased to double of its original length. The percentage increase in the resistance of the wire will be..... $\%$.
    View Solution
  • 8
    Two cells of $emfs$ $E_1$ and $E_2$ and internal resistances $r_1$ and $r_2$ are connected in parallel. The $emf$ and internal resistance of the equivalent source is
    View Solution
  • 9
    Find equivalent resistance between $A$ and $B$
    View Solution
  • 10
    In the given figure each plate of capacitance $C$ has partial value of charge
    View Solution