A heater of $220\, V$ heats a volume of water in $5\,\min$ time. A heater of $110\, V$ heats the same volume of water in ............... $min$
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Heat produced $ = \frac{{{V^2}}}{R}t$
i.e. when voltage is halved, heat produced becomes one-fourth. Hence time taken to heat the water becomes four times.
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