MCQ
A hydrogen atom (ionisation potential $ 13.6\, eV$) makes a transition from third excited state to first excited state. The energy of the photon emitted in the process is.......$eV$
- A$1.89$
- ✓$2.55$
- C$12.09 $
- D$12.75$
✓
Answer
Correct option: B.
$2.55$
b
(b) Energy released$ = 13.6\left[ {\frac{1}{{{{(2)}^2}}} - \frac{1}{{{{(4)}^2}}}} \right] = 2.55\,eV$
(b) Energy released$ = 13.6\left[ {\frac{1}{{{{(2)}^2}}} - \frac{1}{{{{(4)}^2}}}} \right] = 2.55\,eV$
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