A light ray is incident upon a prism in minimum deviation positio… - Vidyadip

MCQ

A light ray is incident upon a prism in minimum deviation position and suffers a deviation of $34^{\circ}$. If the shaded half of the prism is knocked off, the ray will

A
Suffer a deviation of $34^{\circ}$
B
Suffer a deviation of $68^{\circ}$
✓
Suffer a deviation of $17^{\circ}$
D
Not come out of the prism

✓

Answer

Correct option: C.

Suffer a deviation of $17^{\circ}$

By formula $\delta=(n-1) A \Rightarrow 34=(n-1) A$ and in the second position $\delta^{\prime}=(n-1) \frac{A}{2}$
$\therefore \frac{34}{\delta^{\prime}}=\frac{(n-1) A}{(n-1) \frac{A}{2}} \text { or } \delta^{\prime}=\frac{34}{2}=17^{\circ}$

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