Question
A linear programming problem (LPP) along with the graph of its constraints is shown below. The corresponding objective function is
Minimize: $Z=3 x+2 y$. The minimum value of the objective function is obtained at the corner point ( 2 , 0).
The optimal solution of the above linear programming problem $\qquad$
Image

Answer

exists as the inequality $3 x+2 y<6$ does not have any point in common with the feasible region.

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Choose the correct answer from the given four options.If $\text{P}(\text{A})=\frac{2}{5},\text{P}(\text{B})=\frac{3}{5}$ and $\text{P}(\text{A}\cap\text{B})=\frac{1}{5},$ then $\text{P}\Big(\frac{\text{A}'}{\text{B}'}\Big)\cdot\text{P}\Big(\frac{\text{B}'}{\text{A}'}\Big)$ is equas:
Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector $3 \hat{i}+2 \hat{j}-2 \hat{k}$
$\int\frac{\text{x}^3}{\text{x}+1}$ is equal to:
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The vector equation of a line which passes through the point $(2,-4,5)$ and is parallel to the line $\frac{x+3}{3}=\frac{4-y}{2}=\frac{z+8}{6}$ is :
If $\vec{\text{a}}=2\hat{\text{i}}-3\hat{\text{j}}+5\hat{\text{k}},\vec{\text{b}}=3\hat{\text{i}}-4\hat{\text{j}}+5\hat{\text{k}}$ and $\vec{\text{c}}=5\hat{\text{i}}-3\hat{\text{j}}-2\hat{\text{k}},$ then the volume of the parallelopiped with contermious edges $\vec{\text{a}}+\vec{\text{b}},\vec{\text{b}}+\vec{\text{c}},\vec{\text{c}}+\vec{\text{a}}$ is:
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2x + 3y − z = 6
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  2. λ only.
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  4. neither λ nor µ.
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