MCQ
A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base. If the radius of the vessel is $r$ and angular velocity of rotation is $\omega$, then the difference in the heights of the liquid at the centre of the vessel and the edge is
- A$\frac{r \omega}{2 g}$
- ✓$\frac{r^2 \omega^2}{2 g}$
- C$\sqrt{2 g r \omega}$
- D$\frac{\omega^2}{2 g r^2}$
