$\Rightarrow n \propto \frac{1}{{\sqrt m }} $
$\Rightarrow \frac{{{n_1}}}{{{n_2}}} = \sqrt {\frac{{{m_2}}}{{{m_1}}}} $
$ \Rightarrow \frac{n}{{{n_2}}} = \sqrt {\frac{{4m}}{m}}$
$4\Rightarrow {n_2} = \frac{n}{2}$




If the position and velocity of the particle at $t=0\, {s}$ are $2\, {cm}$ and $2\, \omega \,{cm} \,{s}^{-1}$ respectively, then its amplitude is $x \sqrt{2} \,{cm}$ where the value of $x$ is ..... .
