Question
A massless platform is kept on a light elastic spring as shown in fig. When a sand particle of mass $0.1\; kg$ is dropped on the pan from a height of $0.24 \;m$, the particle strikes the pan and spring is compressed by $0.01\; m$.

From what height should the particle be dropped to cause a compression of $0.04\; m$.

Answer

$mg ( h + x )=\frac{1}{2} kx$

mg(0.24+0.01)= $\frac{1}{2} k (0.01)^2$

$mg ( h +0.04)=\frac{1}{2} k (0.04)^2$

$\frac{ h +0.04}{0.24+0.01}=\frac{16}{1}$

$\therefore h +0.4=16 \times 0.25=4$

$h =3.96 \;m$

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