The displacement time equation of a particle executing $SHM$ is : $x = A \,sin\,(\omega t + \phi )$. At time $t = 0$ position of the particle is $x = A/2$ and it is moving along negative $x-$ direction. Then the angle $\phi $ can be
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$\phi=150^{\circ}$
$\mathrm{x}=\mathrm{A} \sin (\omega \mathrm{t}+5 \pi / 6)$
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