MCQ
A motor cycle driver doubles its velocity when he is having a turn. The force exerted outwardly will be
  • A
    Double
  • B
    Half
  • $4$ times
  • D
    $\frac{1}{4}$ times

Answer

Correct option: C.
$4$ times
c
(c) $F = \frac{{m{v^2}}}{r}$ $⇒$ $F \propto {v^2}$ i.e. force will become $4$ times.

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