A parallel plate capacitor is charged. Then battery is removed no… - Vidyadip

MCQ

A parallel plate capacitor is charged. Then battery is removed now If the plates are pulled apart

A
the capacitance increases
✓
the potential difference increases
C
the total charge increases
D
the charge and potential difference remains the same

✓

Answer

Correct option: B.

the potential difference increases

b
${\rm{C}} = \frac{{{ \in _0}{\rm{A}}}}{{\rm{d}}}$ $\quad \quad {\rm{d}} \uparrow \Rightarrow {\rm{c}} \downarrow $

${\rm{V}} = \frac{\sigma }{{{ \in _0}}}{\rm{d}}\quad \quad {\rm{d}} \uparrow \to {\rm{V}} \uparrow $

$\mathrm{Q}=$ constant

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