[ $\epsilon_0$ is the permittivity of free space]
- ✓$1$
- B$3$
- C$5$
- D$6$
[ $\epsilon_0$ is the permittivity of free space]
$K_m=K\left(1+\frac{m}{N}\right)$
$\Rightarrow K_m=K\left(1+\frac{x}{d}\right)$
$C^{\prime}=\frac{K_m A \epsilon_0}{d x}$
$\frac{1}{C_{e q}}=\int_0^d \frac{d x}{K_m A \epsilon_0}=\frac{1}{K A \epsilon_0} \int_0^d \frac{d x}{\left(1+\frac{x}{d}\right)}$
$\Rightarrow \frac{1}{C_{e q}}=\frac{d}{K A \epsilon_0}\left[\ln \left(1+\frac{x}{d}\right)\right]_0^d$
$\Rightarrow \frac{1}{ C _{ eq }}=\frac{ d }{ KA \epsilon_0}[\ln 2-\ell n (1)]$
$\Rightarrow C _{ eq }=\frac{ KA \epsilon_0}{ d \ell n 2} \Rightarrow \alpha=1$
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(Young's modulus of wire $Y =9 \times 10^{10}\, Nm ^{-2}$ ), (to the nearest integer),
Main scale reading : $0 \,\mathrm{~mm}$
Circular scale reading $: 52$ $divisions$
Given that $1\, \mathrm{~mm}$ on main scale corresponds to $100\, divisions$ on the circular scale. The diameter of the wire from the above data is ...... $cm$

Reason : Moving charges produce only electric field in the surrounding space.
