MCQ
A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$
- A$100$
- B$150 $
- ✓$200 $
- D$250 $
✓
Answer
Correct option: C.
$200 $
c
(c) $R = \frac{{{u^2}\sin 2\theta }}{g} = R \propto {u^2}.$ So if the speed of projection doubled, the range will becomes four times,
(c) $R = \frac{{{u^2}\sin 2\theta }}{g} = R \propto {u^2}.$ So if the speed of projection doubled, the range will becomes four times,
i.e., $4 \times 50 = 200\,m$
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